15x^2+8x^2-35=0

Solution for 15x^2+8x^2-35=0 equation:

15x^2+8x^2-35=0

We add all the numbers together, and all the variables

23x^2-35=0

a = 23; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·23·(-35)
Δ = 3220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3220}=\sqrt{4*805}=\sqrt{4}*\sqrt{805}=2\sqrt{805}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{805}}{2*23}=\frac{0-2\sqrt{805}}{46}
=-\frac{2\sqrt{805}}{46}
=-\frac{\sqrt{805}}{23}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{805}}{2*23}=\frac{0+2\sqrt{805}}{46}
=\frac{2\sqrt{805}}{46}
=\frac{\sqrt{805}}{23}
$